Title: Carl’s Carpet
Problem: Carl’s parents said they would redecorate Carl’s bedroom. Carl wants the floor to be covered with separate sections of red, blue, and white carpet, and he wants the sections arranged so the same color isn’t used in two areas that touch.
Carl’s parents told him to draw a picture of how he wants the carpet
to look and to figure out the cheapest way to use the three colors.
They said they’d decide whether they would agree to his plan after they
saw it. Carl drew a plan for the carpet on grid paper. Each small square
is one square yard.
Red = $4.00 per square yard, Blue = $5.00 per square yard, and White = $6. 00 per square yard.
What colors should be used in each of the six areas A - F? How much will it cost to carpet the entire room?
Math Topic/Concept: Measurement, Area, Money
Materials: Graph paper
Classroom Use: (Developmental)
Grade: 3-4
Grade Cluster: (LateElem)
Illinois Goal: 7
Standard: 7A2b
Applied? (1-4): 3
Source: Explain It Grade 3-4 by Creative Publications
Answer: Using Car’s plan, $167.00 would be the lowest price for the carpet.
Strategies Listed: Drawing, Paper and pencil
Solution: Regions A & E have to be the same color and
have an area of 18. Regions C & D have to be the same color and
have an area of 13. Regions B & F have to be the same color and
have an area of 5.
Since the red carpeting is the cheapest, it should be used for the
largest area (A & E). Blue is the next cheapest carpet, so C
& D should be blue. B and F must be white since the touch both red
and blue.
18 sq ft at $4.00 per yd + 13 sq ft at $5.00 per yd + 5 sq ft at $6.00 per yd, or $72.00 + $65.00 + $30.00 = $167.00.
Intended rubric or assessment method: ISAT Rubric
Write-up submitted by: Kathy Erlandson
Problem: Enrique is going to make cards to label the tables at the science fair. He will cut rectangles that are 4 inches wide and 6 inches long from rectangular poster board that is 2 feet wide and 3 feet long. Enrique is measuring and drawing lines to cut along in order to make the greatest number of cards without wasting any of the poster board. How many cards should he have when he is finished? Explain how you find your answer.
Math Topic/Concept: measuring in inches, converting feet to inches, drawing rectangles
Materials: rulers, paper, pencil
Classroom Use: (Developmental)
Grade: 5-6
Grade Cluster: (LateElem)
Illinois Goal: 7 & 9
Standard: 7A2a & 9A2
Applied? (1-4): 3
Source: Explain It Grades5-6 by Creative Publications (ISBN # 0-7622-1598-4)
Answer: 36 cards
Strategies Listed: Draw a picture
Solution: Draw the poster board. Change 2 feet to 24 inches and 3 feet to 36 inches because the cards would be measured in inches. Then I divided the side that was 36 inches long into 6 inch sections to make cards that were 6 inches long. Each card had to be 4 inches wide, and 24 divided by 4 = 6, so 6 cards would fit across. 6 rows of 6 made 36 cards in all.
Intended rubric or assessment method: ISAT rubric
Write-up submitted by: Jonna Young
Problem: Take an 18-inch cubed box and use it to measure the
length, width, and height of your classroom. Using the measurement
in boxes, determine the perimeter, area, and volume of the classroom.
Math Topic/Concept: Measurement, Area, Volume, and Perimeter
Materials: 18-inch square box
Classroom Use: (Developmental)
Classroom use comments*: Perhaps work in groups of 3-5 students
Grade: 4/5
Grade Cluster: (LateElem)
Illinois Goal: 7, 9
Standard: 7A2a, 7B2b, 7C, 9A2a
Applied? (1-4): 2
Source: http://www.isbe.state.il.us/ils/benchmarking/mathactivities.htm#LE
Answer: Will vary according to the measurement of individual classroom.
Strategies Listed: Measurement and the use of formulas for area = length x width, perimeter = sum of all sides of object, and volume = length x width x height. The extension would use the strategy of converting units of measure (inches to feet) or use of scale in a drawing.
Solution: Take the dimensions of the classroom measured in boxes and use the information in the proper formulas to determine answers. For example if the length is 25 boxes, width is 30 boxes, and the height is 12 boxes, the area would be 25 x 30 = 750 boxes, the volume would be 25 x 30 x 12 = 9,000 boxes. The perimeter would be, assuming the room is a rectangle, 25 + 25 + 30 + 30 = 110 boxes.
Other solution methods (if any)*: NA
Extensions or related problems*: Convert the area, perimeter, and volume into total feet. Another option could be to draw a simple scale drawing of the room based on the information gathered from measuring in boxes.
Intended rubric or assessment method:
Assessment ISAT Mathematics Grade 5 Student-Friendly Rubric
www.isbe.state.il.us/isat/rubric5.htm
Notes*: NA
Write-up submitted by: Carl Carlson – Westmer School
Problem: On Friday, April 7, the levee in Keithsburg, Illinois broke due to high waters. As a result, Mrs. McClee’s basement was flooded with a large amount of water. As she cleaned the mess and stopped the water from coming in, she wondered how much water was in her basement. Being very good in math, she remembered that one cubic foot holds 7.48 gallons. When the water stopped coming in she had 2 inches of water covering the backward L-shaped section in the diagram. At that time, Mrs. McClee pulled out her trusty 12-gallon shop vac and got to work.
Questions: How many gallons of water (rounded to the nearest
whole number) were in the basement? When Mrs. McClee had finished
cleaning up, how many times had she emptied her shop vac?
Math Topic/Concept: Volume and Units of Measure
Materials: Copy of the picture
Classroom Use: (Developmental)
Classroom use comments*: Review with the students the concept of a cubic foot.
Grade: 5
Grade Cluster: (LateElem)
Illinois Goal: 7 & 8
Standard: 7A2, 8B2
Applied? (1-4): 3
Source: http://mathforum.com/elempow/print_puzzler.ehtml?puzzle65
Answer: There were 518.4 gallons (Rounded). She would have to empty the shop vac 44 times.
Strategies Listed: Multiplication and division of whole numbers, finding the area and volume.
Solution:
Volume is length x width x height. The
first volume
was the small blue area on the
left bottom corner. The height is 2
inches of water. The volume was
156 in. x 91 in. x 2 in. = 28,392
cubic inches. The second volume
was the large blue area on the right
bottom corner. The length was
240 in. + 91 in. = 331 in. The volume
was 331 in. x 138 in. x 2 in.
= 91,356 cubic inches. The total volume
of the water was 28,392 cubic
in. + 91,356 cubic in. = 119,748 cubic
inches.
A cubic foot is 7.48 gallons. A
cubic foot is also 12 in. x 12 in. x
12 in. = 1,728 cubic inches. I
figured out the number of gallons per
cubic inch by dividing 7.48 gallons
per cubic foot by 1,728 cubic
inches per cubic foot to get .0043287
gallons per cubic inch. I
figured out the gallons in the
basement by multiplying 119,748 cubic
inches x .0043287 gallons per
cubic inch = 518 gallons (rounded).
Could accept 519 or 520 gallons
depending on how they rounded.
I divided the amount of water by
the size of the vac. I divided 518.4
gallons by 12 gallons in the vac
to get 43.2 empties of the vac. Mrs.
McClee could have emptied the
vac 43 times and left a little water in
the vac. I think that Mrs. McClee
wouldn’t leave water in the vac, so
she emptied the vac 44 times.
Other solution methods (if any)*: NA
Extensions or related problems*: The city of Keithsburg’s insurance company has agreed to replace the carpeted area, shown by both the backward L-shape and upside down L-shape on the diagram. To remove the old carpet and replace it costs $15.44 per square yard. How much will the bill for the carpet replacement be (not including tax)?
Mrs. McClee would have to pay $1,034.48.
I got that by getting
the area of the green and blue
parts and multiplying by the price. I
wrote down the areas of the 2
green parts and the 2 blue parts and
added them up. Area is length
times width.
156 in. x 91 in. = 14,196 square
in.
331 in. x 38 in. = 45,678 square
in.
156 in. x 91 in. = 14,196 square
in.
91 in. x 138 in. = 12,558 square
in.
TOTAL
86,628 square in.
A square yard is 36 in. x 36 in.
= 1,296 square inches. I converted
the area to square yards by dividing
86,628 square in. by 1,296
square in. per square yard to
get 67 square yards (rounded). I think
the store would sell whole square
yards, not fractions. He would pay
67 square yards x $15.44 per square
yard or $1,034.48.
Intended rubric or assessment method:
Assessment ISAT Mathematics Grade 5 Student-Friendly Rubric
http://www.isbe.state.il.us/isat/rubric5.htm
Write-up submitted by: Carl Carlson – Westmer School
Problem: Pose this situation: Ben wants to buy a 75-cent snack from a vending machine at the ball game. The machine takes only nickels, dimes and quarters. Ben has 7 nickels, 5 dimes, and 2 quarters. Think about how many ways Ben might be able to pay for the snack with the coins he has. Record your prediction, plan a strategy, and demonstrate all the different ways in which Ben can pay for the 75-cent snack. You can use pictures, make a table or write number sentences. When you think you have found all the ways possible, write down your answer and compare it to your prediction. Write a response to explain your thinking and what you learned in this exercise.
Math Topic/Concept: estimation and computation with currency
Materials: pencil and paper (or math journals) optional: coins for manipulatives
Classroom Use: (Developmental)
Classroom use comments*: Refresh students’ understanding with a brief demonstration of the exchange of a dime with two nickels, two dimes and a nickel for a quarter, etc. Remind students to keep in mind all the important facts of the situation (e.g. Ben has 7N, 5D, and 2Q) – what is KNOWN, what is NOT KNOWN, and what are the RESTRICTIONS.
Grade: 4
Grade Cluster: (LateElem)
Illinois Goal: 6 and 7
Standard: 6.C.2a and 7.A.2b
Applied? (1-4): 3
Source: MPAAC conference discussion
Answer: There are 8 ways
Strategies Listed: look for pattern, use logical reasoning, make a table
Solution: students will most likely develop a T-chart (table) labeled N, D, Q to test and demonstrate the ways. They should also write an explanation of their thinking processes
Other solution methods (if any)*: draw pictures of coins or use manipulatives
Extensions or related problems*: Ask students to find how much change Ben will have left after purchasing his snack. (62 cents). Ask students to select another amount to determine how many ways it might be identified; for example, using only nickels and quarters.
Intended rubric or assessment method: Analytic Scoring Scale (Jim Olsen, WIU)
Write-up submitted by: Rebecca Cummins (Westmer CUSD
203)
Problem: The custodians at Westmer High School have been asked
to plant new grass seed in the area inside the track. Before they
can determine how much grass seed to buy, they need to find the total area.
What is the area inside the track? How did you get your answer?
Information (or provide a diagram): A rectangle with semi-circles on
the ends. The rectange is 100 m by 50 m.
Math Topic/Concept: Area, Diameter, and Circumference
Materials: A copy of the picture and possibly a calculator
Classroom Use: (Developmental)
Grade: 5
Grade Cluster: (LateElem)
Illinois Goal: 7, 10
Standard: 7A2a, 10B2d
Applied? (1-4): 4
Source: Exploring Mathematics Practice – Scott Foresman and Company Grade 5 1995
Answer: 5,157 square meters
Strategies Listed: Area of rectangles, area of circles, multiplication, addition
Solution: I started out by recognizing the rectangle in the diagram. I took the length and multiplied the width to get the area (100m x 50 m = 5,000 square meters). I then took the diameter of the circle on the left, which also serves as the width of the rectangle, and multiplied by 3.14 (50 x 3.14 = 157 meters squared). Since that represents the area of the whole circle, I can use that total to represent the area of the two semi-circles attached to the ends of the rectangle. The total would be 5,000 + 157 = 5, 157 square meters.
Extensions or related problems*: A bag of grass seed at Walmart costs $5.95 (tax included). One bag of grass seed will cover 20 square meters. How many bags will need to be purchased? How much will all the bags of grass seed cost?
I took 5,157 square meters and divided by 20 square meters to figure out how many bags the custodians would need. The answer for 5,157 ÷ 20 = 257 with a remainder of 17, so they would need to purchase 258 bags to have enough to finish the job. The cost is figured out by taking 258 bags and multiplying by $5.95. The answer to 258 x $5.95 = $1,525.10.
Intended rubric or assessment method:
Assessment ISAT Mathematics Grade 5 Student-Friendly Rubric
www.isbe.state.il.us/isat/rubric5.htm
Write-up submitted by: Carl Carlson – Westmer School
Problem: There are two taxi cab companies in Small Town
and they have different rates for determining how much to charge for a
ride.
Speedy Cab Service $3.00 for the
first mile
$0.50 for each additional mile
Whirlwind Cab Company $1.00 per mile
With which cab company would you pay less for a 3-mile ride?
Which cab company would be less expensive for a 10-mile ride?
For what distance ride will the two companies charge exactly the same
amount?
Explain how you find your answers.
Math Topic/Concept: Number sense, addition, currency
Materials: paper, pencil
Classroom Use: (Developmentalaluation)
Grade: 5
Grade Cluster: (LateElem)
Illinois Goal: 6.B.2 , 7.A. 2b and 8.D.2
Standard: 6.B.2 ,7.A.2b and 8.D.2
Applied? (1-4): 3
Source: Explain It! Grades 5-6 from Creative Publications ISBN 0-7622-1598-4
Answer: Whirlwind cab would be less expensive for a 3-mile ride.
They would charge $3.00, while the same distance would cost $4.00 with
Speedy Cab.
For a 10-mile ride, it would be less expensive to use Speedy Cab.
They would charge $7.50 rather than the $10.00 you would be charged by
Whirlwind.
Strategies Listed: While it is a more tedious way to find the
comparative rates for the first 10 miles, making a chart as done in Solution
1 makes it easy to compare the rates for any distance quickly. All
students should understand this approach
Solutions:
Solution 1: You can make a chart showing what the two cab companies
would charge
for each distance up to ten miles. The chart shows that Whirlwind
Cab Company is less expensive for traveling distances less than 5 miles,
and Speedy Cab is less expensive for distances of more than 5 miles.
They are the same price for exactly 5 miles.
Other solution methods (if any)*: Solution 2: Since
Speedy Cab Company charges $0.50 for each mile, except for the first mile,
which is 3 dollars, their charge is $3.00 + $0.50 x the total miles minus
1. For Whirlwind Cab, the charge is $1 x the number of miles.
Speedy Cab costs less for a 3-mile ride, but they charge more for a 10-mile
ride.
For a 3-mile ride:
Speedy Cab = $3+ ($0.50x{3-1}) = $3+$1=$4
Whirlwind Cab = $3.00
For a 10-mile ride:
Speedy Cab = $3.00 + ($0.50 x{10-1})= $3+$4.50 =$9.00
Whirlwind Cab = $10.00
If there is a place where the charge is the same for both companies,
it should be between 3 miles and 10 miles. By checking different
distances, you find that at 5 miles they charge the same rate- $5.00.
Intended rubric or assessment method: Grade 5 "Student-Friendly" Mathematics Scoring Rubric found at http://www.isbe.state.il.us/isat/rubric5.htm
Write-up submitted by: Ann Hulsizer , 5th Grade, Monmouth
Problem: Aiesha earns $15 a day babysitting, and Yvonne earns $8 a day looking after neighbors’ pets. After how many days has Aiesha earned $42 more than Yvonne?
Math Topic/Concept: money, addition , subtraction
Materials: paper and pencil
Classroom Use: (Developmental)
Grade: 5
Grade Cluster: (LateElem)
Illinois Goal: 7
Standard: 7A2
Applied? (1-4): 2
Source: Middle Grades Math – Tools for Success, Prentice Hall (ISBN# 0-13-427709-0)
Answer: 6 days
Strategies Listed: Make a table
Solution: Make a table that shows for each day Aiesha works, she makes $15 more. This pattern needs to be extended. The table must also show Yvonne making $8 more each day she works. The table needs to be extended until the 2 amounts can be subtracted and $42 the answer. Then count the number of days it took.
Day 1 Day 2 Day 3 Day 4 Day 5 Day 6
Aiesha $15 $30 $45 $60 $75 $90
Yvonne $8 $16 $24 $32 $40 $48
Intended rubric or assessment method: ISAT rubric
Write-up submitted by: Jonna Young
Problem: Find the circumference of the circular object.
How did you get your answer?
Radius measured
12.5 inches
Math Topic/Concept: Radius, Diameter, and Circumference
Materials: Copy of the picture of the object and calculators are optional
Classroom Use: (Evaluation)
Classroom use comments*: Review with the class that pi = 3.14
Grade: 5
Grade Cluster: (LateElem)
Illinois Goal: 7
Standard: 7.A.2a
Applied? (1-4): 2
Source: Exploring Mathematics Practice – Scott Foresman and Company
Answer: 78.5 inches
Strategies Listed: Multiplication, Addition, Finding the diameter, Use of Pi
Solution: Since a radius is half of a diameter I took 12.5 x 2 = 25. To find the circumference I took the diameter of 25 inches and x by pi (3.14) = 78.5 inches.
Intended rubric or assessment method: Assessment ISAT Mathematics
Grade 5 Student-Friendly Rubric
www.isbe.state.il.us/isat/rubric5.htm
Write-up submitted by: Carl Carlson – Westmer School
Problem: Katie's mom said that each time Katie didn’t have her daily chore done by supper time, $0.10 would be subtracted from her allowance of $2.25 per week. At the end of the week, Katie received $1.85 for her allowance. How many times was she late doing her chore?
Math Topic/Concept: Number sense, addition, subtraction, and currency
Materials: Paper, pencil
Classroom Use: (Introductory)
Classroom use comments*: Students can work alone and then compare answers with a partner.
Grade: 5
Grade Cluster: (LateElem)
Illinois Goal: 7
Standard: 7.A.2b
Applied? (1-4): 3
Source: Ten Minute Math Mind Stretchers by Laurie Steding ISBN 0-590-86563-3
Answer: 4 times
Strategies Listed: Possible strategies include: Count
up by dimes from $1.85 to $2.25.
You could also write an equation subtracting $1.85 from $2.25.
Then finding the number of dimes in the solution determine the number of
times Katie was late doing her chore.
Solution: Counting up by dimes: $1.85, $1.95, $2.05, $2.15, $2.25, so the answer is four times.
Other solution methods (if any)*: Or in writing the equation, $2.25-$1.85=$0.40, to find the amount subtracted, then determine the number of dimes in $0.40 is 4 dimes or 4 times Katie was late in doing her chore.
Intended rubric or assessment method: Informal Observation
Write-up submitted by: Ann Hulsizer, 5th grade, Monmouth
Problem: On Friday, April 7, the levee in Keithsburg, Illinois
broke due to high waters. As a result, Mrs. McClee’s basement was
flooded with a large amount of water. As she cleaned the mess and stopped
the water from coming in, she wondered how much water was in her basement.
Being very good in math, she remembered that one cubic foot holds 7.48
gallons. When the water stopped coming in she had 2 inches of water
covering the backward L-shaped section in the diagram. At that time,
Mrs. McClee pulled out her trusty 12-gallon shop vac and got to work..
Question: How many gallons of water were in the basement?
When Mrs. McClee had finished cleaning up, how many times had she emptied
her shop vac?
Materials: Copy of the picture
Classroom Use: (Introductory/Developmental/Evaluation)
Grade: 5
Grade Cluster: (EarlyElem/LateElem/MS-Jr.High/EarlyHS/LateHS)
Illinois Goal: 7 & 8
Standard: 7A2, 8B2
Applied? (1-4): 3
Source: http://mathforum.com/elempow/print_puzzler.ehtml?puzzle65
Answer: There were 518.4 gallons(Rounded). She would have to empty the shop vac 44 times. Extension answer: Cost would be $1,034.48.
Strategies Listed: Use a diagram
Solution:
Volume is length x width x height. The
first volume was the small blue area on the left bottom corner. The height
is 2 inches of water. The volume was 156 in. x 91 in. x 2 in. = 28,392
cubic inches. The second volume was the large blue area on the right bottom
corner. The length was 240 in. + 91 in. = 331 in. The volume was 331 in.
x 138 in. x 2 in. = 91,356 cubic inches. The total volume of the water
was 28,392 cubic in. + 91,356 cubic in. = 119,748 cubic inches.
A cubic foot is 7.48 gallons.
A cubic foot is also 12 in. x 12 in. x 12 in. = 1,728 cubic inches. I figured
out the number of gallons per cubic inch by dividing 7.48 gallons per cubic
foot by 1,728 cubic inches per cubic foot to get .0043287 gallons per cubic
inch. I figured out the gallons in the basement by multiplying 119,748
cubic inches x .0043287 gallons per cubic inch = 518.4 gallons (rounded).
I divided the amount of water
by the size of the vac. I divided 518.4 gallons by 12 gallons in the vac
to get 43.2 empties of the vac. Mr. Basden could have emptied the vac 43
times and left a little water in the vac. I think that Mr. Basden wouldn’t
leave water in the vac, so he emptied the vac 44 times.
Bonus: Mr. Basden would have to
pay $1,034.48. I got that by getting the area of the green and blue parts
and multiplying by the price. I wrote down the areas of the 2 green parts
and the 2 blue parts and added them up. Area is length times width. 156
in. x 91 in. = 14,196 square in. 331 in. x 38 in. = 45,678 square in. 156
in. x 91 in. = 14,196 square in. 91 in. x 138 in. = 12,558 square in.
TOTAL
86,628 square in.
A square yard is 36 in. x 36 in.
= 1,296 square inches. I converted the area to square yards by dividing
86,628 square in. by 1,296 square in. per square yard to get 67 square
yards (rounded). I think the store would sell whole square yards, not fractions.
He would pay 67 square yards x $15.44 per square yard or $1,034.48.
Extensions or related problems*: The city of Keithsburg’s insurance company has agreed to replace the carpeted area, shown by both the backward L-shape and upside down L-shape on the diagram. To remove the old carpet and replace it costs $15.44 per square yard. How much will the bill for the carpet replacement be (not including tax)?
Intended rubric or assessment method:
Assessment ISAT Mathematics Grade 5 Student-Friendly Rubric
http://www.isbe.state.il.us/isat/rubric5.htm
Write-up submitted by: Carl Carlson – Westmer School
Problem: Pose this question: “How would you measure a puddle?” Discuss all the kinds of measurements they might be able to use, then brainstorm some ideas about how to measure. Ask students to make estimates for each kind of measure they have suggested. (How deep? How cold? What is the area? How long to run around it? How long would it be if it were a creek instead? )
Math Topic/Concept: measurement (length, weight, volume, time, temperature, etc. according to the generated suggestions)
Materials: have available a great variety of tools for measuring, such as: yarn, meter and yard sticks, rulers, scales, cups, clock with second hand or stopwatch, paperclips, thermometers, etc. Also provide pencil and paper, and A PUDDLE! (Optional: create a classroom puddle by pouring water onto black plastic that is molded into a box of sand.)
Classroom Use: (Developmental)
Classroom use comments*: Review customary and metric units prior to this activity or during the introductory discussion.
Grade: 4
Grade Cluster: (LateElem)
Illinois Goal: 7
Standard: 7.A.2a, 7.B.2a, 7.B.2b
Applied? (1-4): 3
Source: Creative Publications, “Puddle Questions” Investigation 1 (1994)
Answer: various, according to choices made. Check students’ work for accuracy.
Strategies Listed: logical and critical thinking, estimation, computation, measurement, conversion (within and/or between metric and customary)
Solution: Students consider different ways to measure and select appropriate tools. They work with partners to manipulate the measuring tools and to double check readings for accuracy. They record estimates and actual measurements, label units appropriately, and convert within and/or between customary and metric units. You may want students to measure in both systems to begin developing a sense of reasonableness in comparison.
Extensions or related problems*: Apply to measuring liquid in a wading pool, a bath tub, a swimming pool, and other containers. Apply strategies to estimating and measuring even larger bodies of liquid. What about the water tower? What about grain in the silo?
Intended rubric or assessment method: Analytical Scoring Scale (Jim Olsen, WIU)
Write-up submitted by: Rebecca Cummins (Westmer CUSD 203)
James R. Olsen, Western Illinois University
E-mail: jr-olsen@wiu.edu
updated June 27, 2001