Title: “What’s Your Area Code?”
Problem: How many possible area codes are available if all three of
these properties are met:
1)
The first digit can’t be 0 or 1,
2)
The second digit must be 0 or 1
3)
The third digit can be anything
Materials: Pencil, paper, calculator.
Math Topic/Concept: Principles of Counting, Combinations and Permutations, Multiplying Principle of Counting
Classroom Use: Developmental/Evaluation
Classroom Use Comments: Urge students to think of this a digit at a time. Breaking it down and then using the product rule makes this problem much more manageable.
Grade: 11-12
Grade Cluster: Late High School
Illinois Goal: 10
Standard: 10.C.5b
Source: “March Problem Calendar”. Mathematics Teacher. Pg. 200-204. March 2001, Volume 94, Number 3.
Answer: 160 possible area codes
Strategies Used: Draw a picture. Use a calculator
Solution: Eight number choices for the first digit, two number choices for the second digit, and ten number choices for the third digit. Applying the product rule, our solution is 8*2*10= 160 possible area codes.
Extensions or related problems: How many of these area codes begin with the number 8? How many of these area codes begin with an odd digit?
Intended Rubric:
Write-up Submitted by: Scott Epperly
Title: Sock Probability
Problem: A trunk contains a mixture of red socks and blue socks, at most 2000 in all. When two socks are selected randomly without replacement, the probability is one-half that the colors match. What is the largest possible number of red socks in the trunk?
Math Topic/Concept: Probability
Materials: None
Classroom Use: Developmental
Classroom use comments:
This problem uses thought-provoking statistics. It should be used after the topic has been introduced and practiced a bit.
Grade: Statistics course
Grade Cluster: Early HS
Illinois Goal: 10
Standard: 10.C.5.c
Applied? (1-4): level 2
Source: Mathematics Teacher – Volume 93-No. 1- January 2000
Answer: 990
Strategies Listed: Reasoning-possibly acting out some of it.
Solution: Let R and B, respectively, denote the numbers of red and blue socks in the trunk. Because the probability of obtaining a non-matching pair is ½, we have
(R*B)/(R+B choose 2) = ½.
Therefore (by algebraic simplification), (R+B)(R+B-1)=4RB, which can be rewritten (more algebra) as (R-B)^2 = R + B. The total number of socks in the trunk then is a perfect square. Let n = R- B, so that n^2 = R + B. Then (by adding the equations and dividing by 2): R = (n^2 + n)/2
Because R + B <= 2000, then the absolute value of n <= square root of 2000 <45. Thus, the largest possible value of R occurs when n=44, which gives R = 990 (and B = 946).
Other solution methods (if any): none that I know of
Extensions or related problems: many statistic problems could be related to this one
Intended rubric or assessment method:
Notes (if any):
Write-up submitted by: Lisa Wolf
James R. Olsen, Western Illinois University
E-mail: jr-olsen@wiu.edu
updated:
December 16, 2001